Question

A 0.390 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 75.0 pC charge on its surface. What is the potential (in V) near its surface

Answer 1

Answer:

V = 346.15 Volts

Explanation:

Given that,

Diameter of the sphere, d = 0.390 cm

Radius, r = 0.195 cm

Charge, $q=75\ pC =75\times 10^{12}\ C$

The electric potential near its surface is given by :

$V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 75\times 10^{-12}}{0.195\times 10^{-2}}\\\\V=346.15\ V$

So, the potential near its surface is equal to 346.15 V.