Question

Charles's law describes the relationship of the volume and temperature of
gas at a constant mass and pressure. According to this law, what would
happen to the temperature of the gas if its volume decreased from 1.0 L to
0.50 L?
O A. The temperature would decrease by 500 K.
O B. The temperature would double.
O C. The temperature would be reduced by half.
O D. The temperature would increase from 500 K to 1000 K.

Answer 1

Answer:

The temperature would be reduced by half

Explanation:

Charles' Law => V ∝ T =>  V = kT => k = V/T

For two sets of T vs V conditions, the system constant (k) remains unchanged and k₁ = k₂ => V₁/T₁ = V₂/T₂.

Therefore, if V₁ is reduced to 1/2V₁ = V₂ => V₁/T₁ = 1/2V₁/T₂ => V₁/T₁ = V₁/2T₂

and solving for T₂ =>  1/T₁ = 1/2T₂ => 2T₂ = T₁ => T₂ = 1/2T₁

∴ The initial temperature (T₁) would be reduced by half or, T₂ = 1/2T₁