Question

what is the midpoint of this point (-4,2) and (8,0)? ​

Answer 1

Answer:

Mid - point = ( 2 , 1 )

Step-by-step explanation:

Let A = ( - 4 , 2 ) and B = ( 8 , 0 )

Let P = ( x , y ) be the mid-point of AB

Then,

     $P = (\frac{x_A + x_B}{2} , \frac{y_A + y_B}{2} ) \\\\P =(\frac{-4+8}{2} , \frac{2+0}{2}) \\\\P = ( \frac{4}{2} , \frac{2}{2} )\\\\P = ( 2 , 1)$

Answer 2

Answer:

(2,1)

Step-by-step explanation:

Hi there!

Midpoint: $(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )$ where two endpoints of a line segment are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (-4,2) and (8,0)

$(\frac{-4+8}{2} , \frac{2+0}{2} )\\(\frac{4}{2} , \frac{2}{2} )\\(2, 1)$

Therefore, the midpoint of the line segment is (2,1).

I hope this helps!