Respuesta :
Answer:
[tex]P(pink) = P(pink |\ female) = 0.6[/tex]
Step-by-step explanation:
Given
[tex]\begin{array}{ccc}{} & {Male} & {Female} & {Pink} & {156} & {72} \ \\ {Yellow} & {104} & {48} \ \end{array}[/tex]
Required
Why [tex]prefers\ pink\ lemonade[/tex] and [tex]female[/tex] are independent
First, calculate [tex]P(pink |\ female)[/tex]
This is calculated as:
[tex]P(pink |\ female) = \frac{n(pink\ \&\ female)}{n(female)}[/tex]
[tex]P(pink |\ female) = \frac{72}{48+72}[/tex]
[tex]P(pink |\ female) = \frac{72}{120}[/tex]
[tex]P(pink |\ female) = 0.6[/tex]
Next, calculate [tex]P(pink)[/tex]
[tex]P(pink) = \frac{n(pink)}{n(Total)}[/tex]
[tex]P(pink) = \frac{156 + 72}{156 + 72 + 104 + 48}[/tex]
[tex]P(pink) = \frac{228}{380}[/tex]
[tex]P(pink) = 0.6[/tex]
So, we have:
[tex]P(pink) = P(pink |\ female) = 0.6[/tex]
Hence, they are independent
Answer:
P(pink lemonade | female) = P(pink lemonade) = 0.6.
Step-by-step explanation:
A