Questions Diagram is attached below
Answer:
[tex]T=2.08s[/tex]
Explanation:
From the question we are told that:
Speed of Train [tex]V=3.0m.s[/tex]
Angle [tex]\theta=12\textdegree[/tex]
Height of window [tex]h_w=0.90m[/tex]
Width of window [tex]w_w=2.0m[/tex]
The Horizontal distance between B and A from Trigonometric Laws is mathematically given by
[tex]b=\frac{0.9}{tan12}[/tex]
[tex]b=4.23[/tex]
Therefore
Distance from A-A
[tex]d_a=2.0+4.23[/tex]
[tex]d_a=6.23[/tex]
Therefore
Time Required to travel trough d is mathematically given as
[tex]T=\frac{d_a}{v}[/tex]
[tex]T=\frac{6.23}{3}[/tex]
[tex]T=2.08s[/tex]