Respuesta :
Answer:
[tex](x + y+ 1)^2[/tex]
Step-by-step explanation:
[tex]Using : (a + b)^2 = a^2 + 2ab + b^2\\\\(x+ y)^2 + 2(x +y) + 1 , \ where \ a = (x+y) , \ b = 1 \\\\= (x +y)^2 + ( 2 \times 1 \times (x+y)) + 1^2\\\\= (x +y+ 1)^2[/tex]
Step-by-step explanation:
Using:(a+b) ² =a²+2ab+b²
Hope it is helpful to you

