Answer:
No real solutions;
[tex]x=i+1.5[/tex]
Step-by-step explanation:
The easiest method to solve an algebraic equation is to use inverse operations. This applies to the given equation;
[tex](2x-3)^2=-4\\[/tex]
- Take the square root of both sides
[tex]\sqrt{}[/tex]
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As one can see, the right side is a negative number. However, one cannot take the square root of a negative number and get a real result. Therefore, one must use imaginary numbers. Remember, the imaginary unit ([tex]i[/tex]) represents ([tex]\sqrt{-1}[/tex]).
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[tex]2x-3=2i[/tex]
- Add (3) to undo the (-3)
[tex]+3[/tex]
[tex]2x=2i+3[/tex]
- Divide by (2) to remove the coefficient of (2x)
÷[tex]2[/tex] ÷
[tex]x=\frac{2i+3}{2}[/tex]
Simplify,
[tex]x=i+1.5[/tex]