Question

4. Alcohol of mass 21g and density 0.7gcm-3 is mixed with 10g of water. Determine the density
of the mixture. (density of water = 1.0g cm-3)

Answer 1

Answer:

The density of the mixture is 0.775 g/cm³

Explanation:

The given parameters are;

The mass of the alcohol, m₁ = 21 g

The density of the alcohol, ρ₁ = 0.7 g/cm³

The mass of the water with which the alcohol is mixed, m₂ = 10 g

The density of wate, ρ₂ = 1.0 g/cm³

The density of a substance is given by the ratio of the mass to the volume of the substance

The density of the mixture, ρ is given as follows;

$\rho = \dfrac{m_1 + m_2}{\dfrac{m_1}{\rho_1} + \dfrac{m_2}{\rho_2} }$

Therefore;

$\rho = \dfrac{21 + 10}{\dfrac{21}{0.7} + \dfrac{10}{1.0} } = 0.775$

The density of the mixture, ρ = 0.775 g/cm³.