Answer:
y = 2*(x - 3)^2 - 2
Step-by-step explanation:
Remember that a quadratic equation of vertex (h, k) is written as:
y = a*(x - h)^2 + k
Where a is the leading coefficient.
So, if we know that the vertex is at (3, - 2)
we have:
y = a*(x - 3)^2 + (-2)
And we want the y-intercept to be (0, 16)
This means that, when we take x = 0, we must have y = 16
if we replace these in the above equation we get:
16 = a*(0 - 3)^2 - 2
now we can solve this for a
16 = a*(-3)^2 - 2
16 = a*9 - 2
16 + 2 = a*9
18 = a*9
18/9 = a
2 = a
Then the quadratic equation is:
y = 2*(x - 3)^2 - 2
