Respuesta :

Answer:

The equation of the line is [tex]y = 2\cdot x + 3[/tex].

Step-by-step explanation:

The data of the table represents a line, also known as a linear function or a first order polynomial if and only if the following property is satisfied:

[tex]\frac{y_{i+1}-y_{i}}{x_{i+1}-x_{i}} = m, m \in \mathbb{R}[/tex] (1)

Now we proceed to check if the table represents a line instead of another kind of function:

[tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}} = \frac{7-5}{2-1} = 2[/tex]

[tex]\frac{y_{3}-y_{2}}{x_{3}-x_{2}} = \frac{9-7}{3-2} = 2[/tex]

[tex]\frac{y_{4}-y_{3}}{x_{4}-x_{3}} = \frac{13-9}{5-3} = 2[/tex]

[tex]\frac{y_{5}-y_{4}}{x_{5}-x_{4}} = \frac{15-13}{6-5} = 2[/tex]

Hence, the data represents a line. From Geometry we know that the equation of the line can be obtained by knowing two distinct points. The formula of the line is described below:

[tex]y = m\cdot x + b[/tex] (2)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]m[/tex] - Slope.

[tex]b[/tex] - y-Intercept.

If we know that [tex](x_{1}, y_{1}) = (1, 5)[/tex] and [tex](x_{2}, y_{2}) = (6, 15)[/tex], then we have the following system of linear equations:

[tex]m + b = 5[/tex] (1)

[tex]6\cdot m + b = 15[/tex] (2)

The solution of the system of linear equations is: [tex]m = 2[/tex], [tex]b = 3[/tex].

The equation of the line is [tex]y = 2\cdot x + 3[/tex].

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