Solution :
Given :
X = the number of boys in a family of four children
Families having four children are chosen randomly.
The gender distribution in the four child family are equally probable.
Thus,
X P(X) CDF
0 [tex]^4C_0 (1/2)^{4}[/tex] = 1/16 [tex]\frac{1}{16}[/tex]
1 [tex]^4C_1 (1/2)^{4}[/tex] = 1/4 [tex]\frac{5}{16}[/tex]
2 [tex]^4C_2 (1/2)^{4}[/tex] = 3/8 [tex]\frac{11}{16}[/tex]
3 [tex]^4C_3 (1/2)^{4}[/tex] = 1/4 [tex]\frac{15}{16}[/tex]
4 [tex]^4C_4 (1/2)^{4}[/tex] = 1/16 1