Answer:
2(y - 2)(y + 1)
Step-by-step explanation:
Given
2y² - 2y - 4 ← factor out 2 from each term
= 2(y² - y - 2) ← factor the quadratic
Consider the factors of the constant term (- 2) which sum to give the coefficient of the y- term (- 1)
The factors are - 2 and + 1, since
- 2 × 1 = - 2 and - 2 + 1 = - 1 , then
y² - y - 2 = (y - 2)(y + 1)
Then
2y² - 2y - 4 = 2(y - 2)(y + 1) ← in factored form
