Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the triangles CAP and HIT are not given. The general explanation to solve sides of similar triangles is as follows;
[tex]\triangle CAP \sim \triangle HIT[/tex] implies that the following sides are similar:
[tex]CA \to HI[/tex]
[tex]AP \to IT[/tex]
[tex]PC \to TH[/tex]
Take for instance:
[tex]CA = y[/tex] [tex]HI = b[/tex]
[tex]AP = 20[/tex] [tex]IT = 38[/tex]
Then the solution is:
[tex]CA : HI = AP : IT[/tex]
Substitute values for CA, HI, AP and IT
[tex]y : b= 20 : 38[/tex]
Express as fraction
[tex]\frac{y }{ b}= \frac{20 }{ 38}[/tex]
Multiply both sides by b
[tex]y= \frac{20 }{ 38}*b[/tex]
Substitute 19 for b
[tex]y= \frac{20 }{ 38}*19[/tex]
[tex]y= \frac{20 }{ 2}[/tex]
[tex]y=10[/tex]
