23shaydand 23shaydand
  • 28-06-2021
  • Mathematics
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Proportions in similar triangles

Proportions in similar triangles class=

Respuesta :

jimrgrant1 jimrgrant1
  • 28-06-2021

Answer:

x = 4

Step-by-step explanation:

Given that DE is parallel to AC then DE divides the sides proportionally, so

[tex]\frac{BD}{DA}[/tex] = [tex]\frac{BE}{EC}[/tex] , substitute values

[tex]\frac{x+2}{x}[/tex] = [tex]\frac{3}{2}[/tex] ( cross- multiply )

3x = 2(x + 2) ← distribute

3x = 2x + 4 ( subtract 2x from both sides )

x = 4

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