Answer:
To create function h, function f was translated 2 units right
, translated 4 units up and reflected across the x axis
Step-by-step explanation:
Given
[tex]f(x) = x^3[/tex]
[tex]h(x) =-(x + 2)^3 - 4[/tex]
Required
Complete chart
First: f(x) was translated right by 2 units
The rule of right translation is [tex](x,y) \to (x + 2,y)[/tex]
So, we have:
[tex]f'(x) = f(x + 2)[/tex]
[tex]f'(x) = (x + 2)^3[/tex]
Next: f'(x) was translated up by 4 units
The rule of down translation is [tex](x,y) \to (x,y+4)[/tex]
So, we have:
[tex]f"(x) = f'(x) +4[/tex]
[tex]f"(x) = (x + 2)^3 +4[/tex]
Lastly, f"(x) was reflected across the x-axis;
The rule of this reflection is: [tex](x,y) \to (x,-y)[/tex]
So, we have:
[tex]h(x) = -f"(x)[/tex]
[tex]h(x) = -[(x+2)^3 + 4][/tex]
Remove bracket
[tex]h(x) = -(x+2)^3 - 4[/tex]