Answer: The pH of the solution is 13.
Explanation:
pOH is defined as the negative logarithm of hydroxide ion concentration present in the solution.
[tex]pOH=-\log [OH^-][/tex]
We are given:
Concentration of [tex]Ca(OH)_2=0.05mol/dm^3=0.5mol/L[/tex] (Conversion factor: [tex]1L = 1dm^3[/tex] )
1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions
Concentration of [tex]OH^-=(2\times 0.05)=0.1mol/L[/tex]
Putting values in above equation, we get:
[tex]pOH=-\log (0.1)\\\\pOH=1[/tex]
We know:
[tex]pH+pOH=14\\\\pH=14-1\\\\pH=13[/tex]
Hence, the pH of the solution is 13.
