Which compound equalities have x = 2 as a solution? Check all that apply
O 4 < 5x - 1 <10
O4 < 5x - 3 < 10
04 < 5x - 7 < 10
04 < 2x + 1 < 10
04 < 2x + 3 < 10
O 4 < 2x + 6 < 10

Respuesta :

Answer:

[tex](a)\ 4 < 5x - 1 < 10[/tex]

[tex](b)\ 4 < 5x - 3 < 10[/tex]

[tex](d)\ 4 < 2x + 1 < 10[/tex]

[tex](e)\ 4 < 2x + 3 < 10[/tex]

Step-by-step explanation:

Required

Whose solution is [tex]x = 2[/tex]

[tex](a)\ 4 < 5x - 1 < 10[/tex]

Add 1 to both parts

[tex]4 +1< 5x < 10+1[/tex]

[tex]5< 5x < 11[/tex]

Divide through by 5

[tex]1< x<2.2[/tex]

Substitute 2 for x

[tex]1< 2<2.2[/tex] --- this is true

[tex](b)\ 4 < 5x - 3 < 10[/tex]

Add 3 to both parts

[tex]4 +3< 5x < 10+3[/tex]

[tex]7< 5x < 13[/tex]

Divide by 5

[tex]1.4< x < 2.6[/tex]

Substitute 2 for x

[tex]1.4 < 2 < 2.6[/tex] --- this is true

[tex](c)\ 4 < 5x - 7 < 10[/tex]

Add 7 to both parts

[tex]4 +7< 5x < 10+7[/tex]

[tex]12< 5x < 17[/tex]

Divide by 5

[tex]2.4< x < 3.4[/tex]

Substitute 2 for x

[tex]2.4< 2 < 3.4[/tex] --- this is false because 2.4 > 2

[tex](d)\ 4 < 2x + 1 < 10[/tex]

Subtract 1 from all parts

[tex]4 - 1 <2x<10-1[/tex]

[tex]3 <2x<9\\[/tex]

Divide by 2

[tex]1.5 < x < 4.5[/tex]

Substitute 2 for x

[tex]1.5 < 2 < 4.5[/tex] --- this is true

[tex](e)\ 4 < 2x + 3 < 10[/tex]

Subtract 3 from all parts

[tex]4 -3< 2x < 10-3[/tex]

[tex]1 < 2x < 7[/tex]

Divide by 2

[tex]0.5 < x < 3.5[/tex]

Substitute 2 for x

[tex]0.5 < 2 < 3.5[/tex]  ----- this is true

[tex](f)\ 4 < 2x + 6 < 10[/tex]

Subtract 6 from all parts

[tex]4 -6< 2x< 10-6[/tex]

[tex]-2< 2x< 4[/tex]

Divide by 2

[tex]-1< x< 2[/tex]

Substitute 2 for x

[tex]-1< 2< 2[/tex] --- this is false because 2 = 2; not 2 < 2

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