Question

Which of the following equations shows an incorrect relationship between pressures given in
terms of different units?
A) 1.20 atm = 122 kPa
B) 152 mm Hg = 2.03 104 Pa
C) 0.760 atm = 578 mm Hg
D) 1.0 torr = 2.00 mm Hg
E) 1.00 atm = 760 torr

Answer 1

Answer: The correct option is Option D.

Explanation:

Pressure is also a measurement that is expressed in various units. Some of the units are Torr, atm, psi, pascals, mmHg, kPa, and bar

The interconversion of these units are as such:

• For (A):

1 atm = 101.325 kPa

So, 1.20 atm = $\frac{101.325kPa}{1atm}\times 1.20atm=122kPa$

• For (B):

1 mmHg = 133.32 Pa

So, 152 mmHg = $\frac{133.32Pa}{1mmHg}\times 152mmHg=20264.64=2.03\times 10^4Pa$

• For (C):

760 mmHg = 1 atm

So, 0.760 atm = $\frac{760 mmHg}{1atm}\times 0.760atm=578mmHg$

• For (D):

1 mmHg = 1 torr

So, 1.0 torr = $\frac{1 mmHg}{1torr}\times 1torr=1mmHg$

This is an incorrect relationship.

• For (E):

760 torr = 1 atm

Hence, the correct option is Option D.