Question

3x + 1 over 4y2

What is the value of the expression above when x = 3 and y = 4? You must show all work and calculations to receive full credit.

Answer 1

Answer:

5/32

Step-by-step explanation:

(3x+1)/4y^2

(3(3)+1)/[4(4)^2]

(3*3+1)/[4(4)(4)]

(9+1)/[4*16]

10/64

simplify

5/32

Answer 2

The value of the expression at x = 3 and y = 4 is  $\frac{5}{32}$   .

Concept:

• Firstly we will convert the expression into numerical form.
• Then, we will substitute the value of x & y respectively in the expression and simplify it.

How to solve the given question?

• Converting the expression into numerical form.
  ∴ Let $F(x,y) = \frac{3x+1}{4y^2}$
  
• Substituting x = 3 and y = 4 in the given expression.
  ∴$F(x = 3,y =4) = \frac{3(3)+1}{4(4)^2} = \frac{10}{64}$
  ∴ $F(3,4) = \frac{5}{32}$

Thus, the value of the expression at x = 3 and y = 4 is  $\frac{5}{32}$   .

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