Question

If a is a non-zero constant, determine the vertex of y = -3(x + a)^2 - 6

Answer 1

Answer:

Vertex is (-a, -6), where a ≠ 0.

General Formulas and Concepts:

Algebra I

• Coordinates (x, y)
• Quadratics

Algebra II

Vertex Form: y = a(bx - h)² + k

• a is the vertical scale factor
• b is the horizontal scale factor
• (h, k) is the vertex

Step-by-step explanation:

Step 1: Define

y = -3(x + a)² - 6

↓ Identify variables

a = -3

b = 1

(h, k) = (-a, -6)