Use the piecewise function below to evaluate the points f(–3), f(0), and f(–1).

{9x,x−4,x<−1x≥−1
Question 17 options:

f(–3) = –7, f(0) = –0, and f(–1) = 5


f(–3) = –27, f(0) = –4, and f(–1) = 5


f(–3) = –7, f(0) = –4, and f(–1) = –1


f(–3) = –27, f(0) = –4, and f(–1) = –5

Respuesta :

Given:

The piecewise function is:

[tex]f(x)=\begin{cases}9x & \text{ if } x<-1 \\ x-4 & \text{ if } x\geq -1 \end{cases}[/tex]

To find:

The values of [tex]f(-3),f(0), f(-1)[/tex].

Solution:

In the given piecewise function,

[tex]f(x)=9x[/tex] for [tex]x<-1[/tex] and [tex]f(x)=x-4[/tex] for [tex]x\geq -1[/tex].

Putting [tex]x=-3[/tex] in [tex]f(x)=9x[/tex], we get

[tex]f(-3)=9(-3)[/tex]

[tex]f(-3)=27[/tex]

Putting [tex]x=0[/tex] in [tex]f(x)=x-4[/tex], we get

[tex]f(0)=0-4[/tex]

[tex]f(0)=-4[/tex]

Putting [tex]x=-1[/tex] in [tex]f(x)=x-4[/tex], we get

[tex]f(-1)=-1-4[/tex]

[tex]f(-1)=-5[/tex]

The required values are [tex]f(-3)=27,f(0)=-4,f(-1)=-5[/tex].

Therefore, the correct option is D.

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