Answer:
[tex]\displaystyle d = 2\sqrt{13}[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Algebra I
Algebra II
- Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
Step-by-step explanation:
Step 1: Define
Identify
Point (2, 1)
Point (6, 7)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
- Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(6 - 2)^2 + (7 - 1)^2}[/tex]
- [√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{4^2 + 6^2}[/tex]
- [√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{16 + 36}[/tex]
- [√Radical] Add: [tex]\displaystyle d = \sqrt{52}[/tex]
- [√Radical] Simplify: [tex]\displaystyle d = 2\sqrt{13}[/tex]