Answer:
504000 J
Explanation:
Applying,
Δq = cm(Δt)............. Equation 1
Where Δq = change in thermal energy, c = specific heat capacity of water, m = mass of water, Δt = change in temperature.
From the question,
Given: m = 2 kg, Δt = 80-20 = 60°C
Constant; c = 4200 J/kg.°C
Substitute these values into equation 1
Δq = 2(4200)(60)
Δq = 504000 J
Hence the thermal energy is 504000 J
