Answer: The number of phosphorus atoms in given amount of copper(II) phosphate is [tex]8.431\times 10^{24}[/tex]
Explanation:
We are given:
Moles of copper(II) phosphate [tex]Cu_3(PO_4)_2[/tex] = 7.00 mol
1 mole of copper(II) phosphate contains 3 moles of copper, 2 moles of phosphorus and 8 moles of oxygen atoms
Moles of phosphorus in copper(II) phosphate = [tex](2\times 7.00mol[/tex]
According to the mole concept:
1 mole of a compound contains [tex]6.022\times 10^{23}[/tex] number of particles
So, 7.00 moles of copper(II) phosphate will contain = [tex](2\times 7\times 6.022\times 10^{23}=8.431\times 10^{24}[/tex] number of phosphorus atoms.
Hence, the number of phosphorus atoms in given amount of copper(II) phosphate is [tex]8.431\times 10^{24}[/tex]
