Answer:
the answer for this C.
Step-by-step explanation:
are
[tex]area \: of \: a \: sector \: is \: \frac{teter}{360} \times \pi {r}^2 \: [/tex]
[tex]therefore \: it \: is \: equal \: to \: \frac{40}{360} \times \frac{22}{7} \times 8 \times 8 \\ = \frac{40}{360} \times \frac{22}{7} \times 64 [/tex]
[tex]you \: then \: cancel \: 360 \: by \: 40. \\ that \: is \: \frac{1}{9} \times \frac{22}{7} \times 64 \\ \frac{1408}{63} \\ = 22.3.[/tex]