Answer:
[tex]Range=14[/tex]
[tex]\sigma^2 =32.4[/tex]
[tex]\sigma = 5 .7[/tex]
The standard deviation will remain unchanged.
Step-by-step explanation:
Given
[tex]Data: 136, 129, 141, 139, 138, 127[/tex]
Solving (a): The range
This is calculated as:
[tex]Range = Highest - Least[/tex]
Where:
[tex]Highest = 141; Least = 127[/tex]
So:
[tex]Range=141-127[/tex]
[tex]Range=14[/tex]
Solving (b): The variance
First, we calculate the mean
[tex]\bar x = \frac{1}{n} \sum x[/tex]
[tex]\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)[/tex]
[tex]\bar x = \frac{1}{6} *810[/tex]
[tex]\bar x = 135[/tex]
The variance is calculated as:
[tex]\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2[/tex]
So, we have:
[tex]\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2][/tex]
[tex]\sigma^2 =\frac{1}{5}*[162][/tex]
[tex]\sigma^2 =32.4[/tex]
Solving (c): The standard deviation
This is calculated as:
[tex]\sigma = \sqrt {\sigma^2 }[/tex]
[tex]\sigma = \sqrt {32.4}[/tex]
[tex]\sigma = 5 .7[/tex] --- approximately
Solving (d): With the stated condition, the standard deviation will remain unchanged.