Six different​ second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic readings​ (in mmHg) are listed below. Find the​ range, variance, and standard deviation for the given sample data. If the​ subject's blood pressure remains constant and the medical students correctly apply the same measurement​ technique, what should be the value of the standard​ deviation?

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Answer:

[tex]Range=14[/tex]

[tex]\sigma^2 =32.4[/tex]

[tex]\sigma = 5 .7[/tex]

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

[tex]Data: 136, 129, 141, 139, 138, 127[/tex]

Solving (a): The range

This is calculated as:

[tex]Range = Highest - Least[/tex]

Where:

[tex]Highest = 141; Least = 127[/tex]

So:

[tex]Range=141-127[/tex]

[tex]Range=14[/tex]

Solving (b): The variance

First, we calculate the mean

[tex]\bar x = \frac{1}{n} \sum x[/tex]

[tex]\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)[/tex]

[tex]\bar x = \frac{1}{6} *810[/tex]

[tex]\bar x = 135[/tex]

The variance is calculated as:

[tex]\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2[/tex]

So, we have:

[tex]\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2][/tex]

[tex]\sigma^2 =\frac{1}{5}*[162][/tex]

[tex]\sigma^2 =32.4[/tex]

Solving (c): The standard deviation

This is calculated as:

[tex]\sigma = \sqrt {\sigma^2 }[/tex]

[tex]\sigma = \sqrt {32.4}[/tex]

[tex]\sigma = 5 .7[/tex] --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

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