Answer:
[tex]\theta = 82.2^\circ[/tex]
Step-by-step explanation:
[tex]Let \ \angle BAC = \theta[/tex]
Opposite = BC ,
Adjacent = AB = x = 3 ,
Hypotenuse = AC = y = 22
Using trigonometric ratios.
[tex]sin \theta = \frac{opposite}{hypotenuse }\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}[/tex]
Since we have adjacent and hypotenuse we use cosine's ratio
to find the angle.
[tex]cos \theta = \frac{x}{y} = \frac{3}{22} \\\\\theta = cos^{-1} \frac{3}{22} = 82.16 = 82.2^\circ[/tex]
