What is the area of a sector when 0=90° and r= 8/3?

Answer:
16π/9
Step-by-step explanation:
the area of sector= ¼×π.r²
= ¼× π× (8/3)²
= ¼×64/9×π
= 16π/9
Answer:
Answer:
16π/9
Step-by-step explanation:
the area of sector= ¼×π.r²
= ¼× π× (8/3)²
= ¼×64/9×π
= 16π/9
Step-by-step explanation: