Question

which equation is the inverse of the y=7×^2-10?​

Answer 1

Answer:

option B

Step-by-step explanation:

Given :

 $y = 7x^2 - 10$

Replace x and y :

  $x = 7y^2 - 10$

Now solve for y :

$x = 7y^2 - 10 \\\\x + 10 = 7y^2 - 1 0+ 10$                               $[ \ adding \ 10 \ on \ both \ sides \ ]$

$x + 10 = 7y^2\\\\\frac{x + 10 }{7 } = \frac{7y^2}{7}$                                              $[ \ dividing\ by \ 7 \ on \ both \ sides \ ]$

$\frac{x+ 10}{7} = y^2\\\\\pm \ \sqrt{\frac{x+ 10}{7}} = y$

Answer 2

I think the choose (2)

$y = - + \sqrt{ \frac{x + 10}{7} }$