Answer:
Explicit
gn = 3(1/3)^(n-1)
Recursive
gn =1/3gn-1
Step-by-step explanation:
3 , 1 , 1/3 , 1/9 . . .
gn = ar^(n-1)
Where,
a = first term = 3
r = common ratio = 1/3
Check:
g2 = ar^(n-1)
= 3(1/3)^(2-1)
= 3/3^(1)
= 1^1
= 1
The explicit formula is
gn = ar^(n-1)
gn = 3(1/3)^(n-1)
The recursive form for a geometric sequence is gn = rgn-1
recursive form for our sequence gn =1/3gn-1
Where,
gn = 3
