Question

Find the total surface area of this square based pyramid. 10 in 5 in [ ? ]in?​

Answer 1

Answer:

The answer is "$125 \ in^2$"

Step-by-step explanation:

There is a base of five on every triangular face and a height of ten in. The field of the formulation

$A = (\frac{1}{2})bh \\\\A = (\frac{1}{2} \times 5\ in \times 10\ in)$

   $= \frac{50 }{2} \ in^2\\\\=25 \ in^2$

The base of the square has a formula area

 $A = s^2 = (5\ in)^2 = 25 \ in^2$

The total area consists of the sum of the four-face area and the base: $total \ \ area = 4 \times \text{(area of 1 face) + (area of base)}$

                   $= 4 \times (25\ in^2 ) + 25 \ in^2 \\\\= 125 \ in^2$