Question

Rationalise the denominator and simplify:

7/√7

Answer 1

$\implies {\blue {\boxed {\boxed {\purple {\sf {√7}}}}}}$

$\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}$

$=\frac{7}{ \sqrt{7} }$

$= \frac{7}{ \sqrt{7} } \times \frac{ \sqrt{7} }{ \sqrt{7} }$

$= \frac{7 \sqrt{7} }{ \sqrt{7} \times \sqrt{7} }$

$= \frac{7 \sqrt{7} }{7}$

$(∵ \sqrt{a} \times \sqrt{a} = a)$

$= √7$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}$

Answer 2

Step-by-step explanation:

Given,

7/√7

The denominator is √7.

We know that

Rationalising factor of √a is √a.

Therefore, the rationalising factor of √7 is √7.

On rationalising the denominator them

=> (7/√7) × (√7/√7)

=> 7(√7)/(√7 × 7)

=> 7√7/7.

Hence, the denominator is rationalised.