Answer:
2sinxcosx - cosx OR cosx(2sinx - 1)
Step-by-step explanation:
Use the double angle identity for sin2x.
sin2x = 2sinxcosx
Substitute sin2x with 2sinxcosx.
2sinxcosx - cosx
Factor out cosx, if needed.
cosx * (2sinx - 1)
Answer:
[tex]{ \tt{ \sin2x - \cos x }} \\ = { \tt{(2 \sin x \cos x) - \cos x }} \\ = { \tt{ \cos x(2 \sin x - 1) }}[/tex]
