In the diagram below. De and Ef are tangent to 0. Which equation could be solved to find y, the measure of DGF? O A. ;(-127) = 53 OB. }(v + 127) = 53 O c. }(y-53) = 127 OD. } (x + 53) = 127

The intercepted arc exists the arc that exists inside the inscribed angle and whose endpoints exist on the angle. The vertex of an inscribed angle can be anywhere on the circle as stretched as its sides intersect the circle to construct an intercepted arc.

Let, DE and EF exist as tangents to O.

The value of y will be evaluated as follows:

For angle created outside of circle by intersection:

Two tangents or two secants or a tangent and a secant, the formula for angle created outside will be:

An angle formed outside = 1/2(Difference of Intercepted Arcs)

An angle formed outside exists ∠DEF = 53°

Intercepted arcs exist y and 127°

Hence, 53 = 1/2(y -127)

Therefore, the correct answer is option C). 1/2(y -127) = 53.

To learn more about intercepted arcs refer to:

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In the diagram below. De and Ef are tangent to 0. Which equation could be solved to find y, the measure of DGF? O A. ;(-127) = 53 OB. }(v + 127) = 53 O c. }(y-53) = 127 OD. } (x + 53) = 127​

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What is intercepted arc?

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In the diagram below. De and Ef are tangent to 0. Which equation could be solved to find y, the measure of DGF? O A. ;(-127) = 53 OB. }(v + 127) = 53 O c. }(y-53) = 127 OD. } (x + 53) = 127