Question

Which of the following represents the factorization of the trinomial below?
x2 - 14x + 49
O A. (x-7)
O B. (x-7)(x+7)
O C. (x+7)
O D. (x+2)(x+7)
ANSWER ASAP!!

Answer 1

the answer should be B!

Answer 2

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: ( {x - 7})^{2} }}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

${x}^{2} - 14x + 49$

$= {x}^{2} - 7x - 7x + 49$

Taking "$x$" as common from first two terms and "7" from last two terms, we have

$= x \: ( \: x - 7 \: ) - 7 \: ( \: x - 7 \: )$

Taking the factor $(x-7)$ as common,

$= ( \: x - 7\:) \: (\: x - 7\: )$

$=( {x - 7})^{2}$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$