An object is fired from the ground at 100. m/s at an angle of 30° with the horizontal.
a) Calculate the horizontal and vertical components of the initial velocity
b) After 2.0 seconds, how far has the object traveled in the horizontal direction?
c) How high is the object at this point

Respuesta :

Answer:

a. V_y = 50m/s and V_x = 86.6m/s

b. d_x = 173.2m

c. d_y = 80.38m

Explanation:

V_x = 100m/s*cos(30°)

V_x = 86.6m/s

V_y = 100m/s*sin(30°)

V_y = 50m/s

D_x = v_x*t

d_x = 86.6m/s*2s

d_x = 173.2m

v_f = 50m/s+(-9.81m/s²)*2s

v_f = 30.38m/s

d_y = .5*(30.38m/s+50m/s)*2s

d_y = 80.38m

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