Answer:
[tex]cot\theta=-\frac{5}{12}[/tex]
Step-by-step explanation:
We are given that the point (5,-12) lies on the terminal side of an angle theta in standard position.
We have to find the exact value of [tex]cot\theta[/tex].
Let
Point (x,y)=(5,-12)
[tex]r=\sqrt{x^2+y^2}[/tex]
Substitute the values
[tex]r=\sqrt{5^2+(-12)^2}[/tex]
[tex]r=\sqrt{169}=13[/tex]
We know that
[tex]cot\theta=\frac{x}{y}[/tex]
Using values
[tex]cot\theta=-\frac{5}{12}[/tex]