Respuesta :
Answer:
x<=-3
Step-by-step explanation:
2x-5/x-2 <= 1
Multiply both sides by x-2
2x-5<=x-2 (anything times 1 is that number.)
add 5 to both sides
2x<=x-3
subtract x from both sides
x<=-3
Answer:
Step-by-step explanation:
[tex]\frac{2x-5}{x-2} \leq 1\\case ~1. both ~numerator~and~denominator \geq 0\\x\neq 2\\2x-5\leq x-2\\x\leq 3\\so~0\leq x<2U2<x\leq 3\\case~2.\\both~numerator~and~denominator<0\\2x-5\geq x-2\\x>3\\which~is~rejected~as~it~gives~both~2x-5~and ~x-2>0[/tex]
