Answer:
b. [tex] \frac{1}{16} [/tex]
Step-by-step explanation:
A = {2, 3}
B = {4, 6}
C = set of all possible fractions where, the numerators are in set A and the denominators are found in Set B
The 4 possible fractions we can get for set C are as follows:
Set C: { [tex] \frac{2}{4} [/tex] , [tex] \frac{2}{6} [/tex] , [tex] \frac{3}{4} [/tex] , [tex] \frac{3}{6} [/tex] }
Multiply all to get the product of all elements in Set C:
[tex] \frac{2}{4}*\frac{2}{6}*\frac{3}{4}*\frac{3}{6} [/tex]
Simplify where necessary
[tex] \frac{1}{2}*\frac{1}{3}*\frac{3}{4}*\frac{1}{2} [/tex]
[tex] \frac{1*1*3*1}{2*3*4*2} [/tex]
[tex] \frac{3}{48} [/tex]
Simply further
[tex] \frac{1}{16} [/tex]
