I’m confused a little please help
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Answer:
m∠E = 60°
Step-by-step explanation:
The given information in the diagram are;
The shape of the drawing, ΔEDF = A right triangle
The length of the hypotenuse side opposite the right angle = 16·√46
The length of the leg adjacent to the reference angle ∠E = 8·√46
By trigonometric ratio, we have;
[tex]\dfrac{Adjacent\ leg \ length}{Hypotenuse \ length} = cos\angle E[/tex]
Plugging in the values gives;
[tex]cos\angle E = \dfrac{8 \cdot \sqrt{46} }{16\cdot \sqrt{46} } = \dfrac{1}{2}[/tex]
∴ m∠E = arccos(1/2)
Using a calculator or from tables or an online trigonometric ratio tool, we have
arccos(1/2) = 60°
∴ m∠E = arccos(1/2) = 60°.