The image to the question is attached below.
Answer: The value of EN is 11.2 cm
Step-by-step explanation:
We are given:
The parallelograms ABCD and EFGH are congruent, which simply means
AB = EF
BC = FG
CD = GH and
AD = EH
Area of ABCD = area of EFGH
Also, opposite sides of a parallelogram are equal. Thus,
AB = EF = CD = GH
BC = FG = AD = EH
It is given:
[tex]AD=10cm=FG\\\\\text{Area of ABCD}=112cm^2=\text{Area of EFGH}[/tex]
To calculate the area of a parallelogram, we use the equation:
[tex]Area=b\times h[/tex]
where, for parallelogram EFGH
b = base = FG = 10 cm
h = height = EN = ?
Area = [tex]112cm^2[/tex]
Plugging values in above equation, we get:
[tex]112cm^2=10cm\times EN\\\\EN=\frac{112cm^2}{10cm}=11.2cm[/tex]
Hence, the value of EN is 11.2 cm
