Respuesta :

The answer is 1/x^2y^2

The given expression is [tex] \frac{ {x}^{0} y { - }^{3} }{ {x}^{2}y { - }^{1} } [/tex]

We know that any number raised with zero power equals 1. Thus, [tex] {x}^{0} = 1[/tex]

Hence, the expression becomes

[tex] \frac{y { - }^{3} }{ {x}^{2} y { - }^{1} } [/tex]

Now, apply the quotient rule,[tex] \frac{ {x}^{ \alpha } }{ {x}^{b} } = {x}^{ \alpha - b} [/tex]

Using this rule, we have

[tex] \frac{1}{ {x}^{2} y { - }^{1 - ( - 3)} } [/tex]

[tex] = \frac{1}{ {x}^{2} y { - }^{1 + 3} } [/tex]

[tex]= \frac{1}{ {x}^{2} {y}^{2} } [/tex]

Hence, the simplified expression is [tex] \frac{1}{ {x}^{2} {y}^{2} } [/tex]

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