Question

You have 4 litres of a 3.0 mol/L solution of NaCl in a
chemical store room.
How many moles of NaCl are present? *

0.75 mol

1.33 mol

12 mol

Answer 1

Given:

M = 3.0 mol/L

V = 4 L

Required:

n

Solution:

M = n / V

n = MV

n = (3.0 mol/L)(4 L)

n = 12 mol

Therefore, the number of moles of NaCl present is 12 mol.

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Answer 2

Answer 12 mol

Explanation: $C_{M} = \frac{n}{V} ==> n = C_{M} *V=4*3=12 mol$