Question

a car starts from rest & acquire a velocity of 54km/h in 2 sec. Find-
a) the acceleration
b) distance traveled by car assume motion of car is uniform
c) if the mass of the car is 1000kg. what is the force acting on it?
Pls help me. I'm bad in this subject. kinda need it by today​

Answer 1

Answer:

a. Acceleration, a = 7.5 m/s

b. Distance, S = 15 meters

c. Force = 7500 Newton

Explanation:

Given the following data;

Mass = 1000 kg

Initial velocity = 0 m/s (since it's starting from rest).

Final velocity = 54 km/h

Time = 2 secs

Conversion:

54 km/h to m/s = 54*1000/3600 = 15 m/s

a. To find the following acceleration;

Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{initial speed - final speed}{time}$

Substituting into the formula, we have;

$Acceleration = \frac{15 - 0}{2}$

$Acceleration = \frac{15}{2}$

Acceleration, a = 7.5 m/s

b. To find the distance, we would use the second equation of motion.

$S = ut + \frac {1}{2}at^{2}$

Where;

• S represents the displacement or height measured in meters.
• u represents the initial velocity measured in meters per seconds.
• t represents the time measured in seconds.
• a represents acceleration measured in meters per seconds square.

Substituting into the equation, we have;

$S = 0*2 + \frac {1}{2}*(7.5)*2^{2}$

$S = 0 + 3.75*4$

$S = 15$

Distance, S = 15 meters

c. To find the force, we would use the following formula;

$Force = mass * acceleration$

$Force = 1000 * 7.5$

Force = 7500 Newton