Answer:
The mean of the random variable is 0.
The variance of the random variable is [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
We are given the following probability distribution:
[tex]P(X = -2) = \frac{1}{8}[/tex]
[tex]P(X = -1) = \frac{2}{8}[/tex]
[tex]P(X = 0) = \frac{2}{8}[/tex]
[tex]P(X = 1) = \frac{2}{8}[/tex]
[tex]P(X = 2) = \frac{1}{8}[/tex]
Mean:
Sum of each value multiplied by its probabilities. So
[tex]E(X) = -2\frac{1}{8} -1\frac{2}{8} + 0\frac{2}{8} + 1\frac{2}{8} + 2\frac{1}{8} = \frac{-2 -1 0 + 1 + 2}{8} = \frac{0}{8} = 0[/tex]
The mean of the random variable is 0.
Variance:
Sum of the difference squared between each value and the mean, multiplied by its probabilities. So
[tex]V(X) = \frac{1}{8}(-2-0)^2 +\frac{2}{8}(-1-0)^2 + \frac{2}{8}(0-0)^2 + \frac{2}{8}(1-0)^2 + \frac{1}{8}(2-0)^2 = \frac{4 + 2 + 0 + 2 + 4} = \frac{12}{8} = \frac{3}{2}[/tex]
The variance of the random variable is [tex]\frac{3}{2}[/tex]