the answer is Cr in Cr2O7.
Explanation:
it's oxidation number is +7 in the compound
while Fe has +3 and P has +6 in their respective compounds
The oxidation state is the gained or lost electrons by an atom to create a chemical bonding. Chromium (Cr) in Cr₂O₂⁻⁷ has the highest oxidation state. Thus, option C is correct.
Oxidation is the representation of the electrons that are lost and gained by an element in a molecule or compound to establish a chemical bond. The oxidation number of free elements is always zero, and hydrogen is usually +1.
The oxidation state of P in H₂PO⁻₄ is given as,
2 (1) + P + 4(-2) = -1
P = + 5
The oxidation number of Fe in Fe₂O₃ is given as,
2Fe + 3O = 0
2Fe + 3(-2) = 0
Fe = + 3
The oxidation number of Cr in Cr₂O₂⁻⁷ is given as,
2Cr + 7O = -2
2Cr + 7(-2) = -2
Cr = + 6
Therefore, chromium (+6) in Cr₂O₂⁻⁷ has the highest oxidation state.
Learn more about the oxidation state here:
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