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2 Answers:

  • Choice A
  • Choice E

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Explanation:

Let's go through the answer choices

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A)

The lowest point is y = 1, and the highest point is y = 27. Computing the midpoint gets us (yMin+yMax)/2 = (1+27)/2 = 28/2 = 14.

The midline of [tex]h(\theta)[/tex] is y = 14.

Consider that the parent function [tex]\cos(\theta)[/tex] has a midline of y = 0. The jump from y = 0 to y = 14 must mean [tex]h(\theta)[/tex] has a vertical shift of 14.

Choice A is true

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B)

The period is the length of the cycle. For the function [tex]h(\theta)[/tex], the function starts at [tex]\theta = 0[/tex] and repeats when it gets to [tex]\theta = \frac{\pi}{2}[/tex]. This is a difference of pi/2 units which is the period.

Choice B is false. It contradicts with choice E.

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C)

Choice C is false. The max for [tex]h(\theta)[/tex] is at y = 27

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D)

To figure out the amplitude, we can note the vertical distance from the midline y = 14 to the max is 27-14 = 13 units.

Or we can note the distance from the midline to the min is 14-1 = 13 units.

Or we subtract the min and max, and divide by 2:  (yMax-yMin)/2 = (27-1)/2 = 26/2 = 13

Either way, the amplitude is 13 units

Choice D is false.

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E)

Choice E is true. Refer to choice B to see why this is the case.

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Side note: one possible function is [tex]h(\theta) = 13\cos(4\theta+\pi) + 14[/tex]. The various pieces of that function (in)directly lead to the amplitude, period, and vertical shift.

The correct two options are h(Ф) has vertical shift of 14 and Choice E

The period of a fuction is x/2

What is a function?

A function is defined as the expression that set up the relationship between the dependent variable and independent variable.

Let's go through the answer choices

A)

The lowest point is y = 1, and the highest point is y = 27. Computing the midpoint gets us (yMin+yMax)/2 = (1+27)/2 = 28/2 = 14.

The midline of  is y = 14.

Consider that the parent function  has a midline of y = 0. The jump from y = 0 to y = 14 must mean  has a vertical shift of 14.

Choice A is true

B)

The period is the length of the cycle. For the function , the function starts at  and repeats when it gets to . This is a difference of pi/2 units which is the period.

Choice B is false. It contradicts with choice E.

C)

Choice C is false. The max for  is at y = 27

D)

To figure out the amplitude, we can note the vertical distance from the midline y = 14 to the max is 27-14 = 13 units.

Or we can note the distance from the midline to the min is 14-1 = 13 units.

Or we subtract the min and max, and divide by 2:  (yMax-yMin)/2 = (27-1)/2 = 26/2 = 13

Either way, the amplitude is 13 units

Choice D is false.

E)

Choice E is true. Refer to choice B to see why this is the case.

Side note: one possible function is h(Ф) = 13 Cos(4Ф + π) + 14 . The various pieces of that function (in)directly lead to the amplitude, period, and vertical shift.

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