Consider y=h(θ) described in the table. When comparing h(θ) to the parent function f(θ)=cos(θ), which statements are true? Select all that apply.
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2 Answers:
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Explanation:
Let's go through the answer choices
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A)
The lowest point is y = 1, and the highest point is y = 27. Computing the midpoint gets us (yMin+yMax)/2 = (1+27)/2 = 28/2 = 14.
The midline of [tex]h(\theta)[/tex] is y = 14.
Consider that the parent function [tex]\cos(\theta)[/tex] has a midline of y = 0. The jump from y = 0 to y = 14 must mean [tex]h(\theta)[/tex] has a vertical shift of 14.
Choice A is true
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B)
The period is the length of the cycle. For the function [tex]h(\theta)[/tex], the function starts at [tex]\theta = 0[/tex] and repeats when it gets to [tex]\theta = \frac{\pi}{2}[/tex]. This is a difference of pi/2 units which is the period.
Choice B is false. It contradicts with choice E.
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C)
Choice C is false. The max for [tex]h(\theta)[/tex] is at y = 27
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D)
To figure out the amplitude, we can note the vertical distance from the midline y = 14 to the max is 27-14 = 13 units.
Or we can note the distance from the midline to the min is 14-1 = 13 units.
Or we subtract the min and max, and divide by 2: (yMax-yMin)/2 = (27-1)/2 = 26/2 = 13
Either way, the amplitude is 13 units
Choice D is false.
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E)
Choice E is true. Refer to choice B to see why this is the case.
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Side note: one possible function is [tex]h(\theta) = 13\cos(4\theta+\pi) + 14[/tex]. The various pieces of that function (in)directly lead to the amplitude, period, and vertical shift.
The correct two options are h(Ф) has vertical shift of 14 and Choice E
The period of a fuction is x/2
A function is defined as the expression that set up the relationship between the dependent variable and independent variable.
Let's go through the answer choices
A)
The lowest point is y = 1, and the highest point is y = 27. Computing the midpoint gets us (yMin+yMax)/2 = (1+27)/2 = 28/2 = 14.
The midline of is y = 14.
Consider that the parent function has a midline of y = 0. The jump from y = 0 to y = 14 must mean has a vertical shift of 14.
Choice A is true
B)
The period is the length of the cycle. For the function , the function starts at and repeats when it gets to . This is a difference of pi/2 units which is the period.
Choice B is false. It contradicts with choice E.
C)
Choice C is false. The max for is at y = 27
D)
To figure out the amplitude, we can note the vertical distance from the midline y = 14 to the max is 27-14 = 13 units.
Or we can note the distance from the midline to the min is 14-1 = 13 units.
Or we subtract the min and max, and divide by 2: (yMax-yMin)/2 = (27-1)/2 = 26/2 = 13
Either way, the amplitude is 13 units
Choice D is false.
E)
Choice E is true. Refer to choice B to see why this is the case.
Side note: one possible function is h(Ф) = 13 Cos(4Ф + π) + 14 . The various pieces of that function (in)directly lead to the amplitude, period, and vertical shift.
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