Question

In triangle ABC, AB = 11 cm, BC = 9 cm and CA = 10 cm.
Find the area of triangle ABC.

Answer 1

Answer:

Area = 42.43 square cm

Step-by-step explanation:

Using Heron's Formula :

 $Area = \sqrt{s\times (s-a) \times (s-b) \times(s -c)} \ , \ where \ s \ =\ \frac{a+ b+ c}{2}$

Find Area :

$s = \frac{11 + 9 + 10 }{2} = \frac{30}{2} = 15$

$Area = \sqrt{15 \times ( 15 - 11 ) \times { (15 - 9 ) \times ( 15 -10)}$

      $= \sqrt{15 \times 4 \times 6 \times 5}\\\\=\sqrt{1800}$

      $= 42 . 43 \ cm^2$