Question

what would be the mass of 44.8 L of CO2 gas at STP?
show work if possible

Answer 1

Answer:

$m=88.02g$

Explanation:

Hello there!

In this case, for this ideal gas law problem, it turns out necessary for us to remember that one mole of any gas is contained in 22.4 L at STP and therefore, we can use the following ratio to calculate the moles in 44.8 L of CO2:

$\frac{1mol}{22.4L} =\frac{x}{44.8L}\\\\x= \frac{1mol*44.8L}{22.4L}=2mol$

Finally, since the molar mass of CO2 is 44.01 g/mol, we calculate the mass as follows:

$m=2mol*\frac{44.01g}{1mol}\\\\m=88.02g$

Regards!