Question

An object is launched from the roof of a building 192
feet above the ground. The object's height (in feet)
after t seconds is given by the function
h(t) = -16° +64t + 192
A) What is the height of the object after two-and-a-half
seconds?
252 ft
256 ft
312 ft
620 ft

Answer 1

Answer:

252 ft

Step-by-step explanation:

h(t) = -16t^2 +64t + 192

We want to find h when t= 2.5

h(2.5) = -16 (2.5)^2 +64(2.5) +192

          =-16(6.25) +160+192

            =-100+160+192

               =252

Answer 2

252 ft



s
s
s
ss
s
s
s
s
s
s
sssss
s
s
s